Stoichiometry, find the mass of the product

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SUMMARY

The discussion focuses on calculating the theoretical mass of methyl salicylate produced from the reaction of 1.20 grams of salicylic acid with excess methanol. The molar masses are specified as 138.13 g/mol for salicylic acid, 32.05 g/mol for methanol, and 152.16 g/mol for methyl salicylate. The calculations confirm that 1.32 grams of ester can be expected based on a 1:1:1 mole ratio. The use of excess methanol does not affect the result, as it is not a limiting reagent in this scenario.

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SelenaT
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Homework Statement



[/B]
If 1.20 grams of salicylic acid is reacted with excess methanol, what mass of ester should you expect to achieve theoretically?

Molar masses of..
salicylic acid is 138.13g/mol
methanol is 32.05g/mol
ester (methyl salicylate) is 152.16g/mol

Mole ratio
1:1:1

Homework Equations

3. The Attempt at a Solution
[/B]

1. 1.20 g salicylic acid (1 mol salicylic acid/138.13 g salicylic acid) = 0.008687468 mol salicylic acid

2. 0.008687468 mol salicylic acid (1 mol ester/1 mol salicylic acid) = 0.008687468 mol ester

3. 0.008687468 mol ester (152.16 g ester/1 mol ester) = 1.32 g ester

so 1.32g of ester would be expected.

Is my work correct? or do I have to use the excess reagent to find the mass of the product?
 
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Looks good. Any reason to suspect "xs" would change your result?
 

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