Stokes' Theorem: Finding the Flux of a Vector Field on a Surface

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Homework Help Overview

The discussion revolves around applying Stokes' Theorem to find the flux of a vector field, specifically the vector field \(\vec{F} = xy\vec{i} + yz\vec{j} + xz\vec{k}\) over a surface defined by \(z = 9 - x^2\) within specified bounds. Participants are exploring the relationship between the surface and its boundary, as well as the necessary vector area elements.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss finding the curl of the vector field and the subsequent steps needed to apply Stokes' Theorem. There is a focus on determining the vector area element and the normal vector to the surface, with some participants seeking clarification on terminology and methods for parameterization.

Discussion Status

The discussion is active, with participants providing guidance on how to find the normal vector and suggesting the use of sketches to visualize the surface. There is an ongoing exploration of the necessary mathematical concepts, but no consensus has been reached on the specific steps to take next.

Contextual Notes

Participants are navigating the definitions and calculations related to vector area elements and normal vectors, indicating a potential gap in foundational understanding that is being addressed through dialogue.

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Homework Statement



Let [tex]\vec{F} = xy\vec{i} + yz\vec{j} + xz\vec{k}[/tex] and C is the boundary of S, the surface z = 9 - x2 for 0 ≤ x ≤ 3 and -6 ≤ y ≤ 6, oriented upward. Use Stokes' Theorem to find [tex]\int\limits_c \vec{F} \cdot d\vec{r}.<br /> <br /> <h2>Homework Equations</h2><br /> <h2>The Attempt at a Solution</h2><br /> <br /> well I've found the curlF at least.. I don't know what I should do now[/tex]
 
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Find an expression for the vector area element of S (it should have an x-component and a z-component)and integrate over the surface.
 


vectore area element??
 


Yes, it's the product of the infinitesimal area element (usually denoted [itex]dS[/itex] or [itex]da[/itex]) with the unit normal to the surface ([itex]\vec{da}=\hat{n}da[/itex]). Have you not heard that term before?

For example, the outward vector area element for a spherical shell of radius [itex]R[/itex] is [itex]\vec{da} =R^2 \sin \theta d \theta d \phi \hat{r}[/itex], where [itex]\theta[/itex] is the polar angle, [itex]\phi[/itex] is the azimuthal angle, and [itex]\hat{r}[/itex] (sometimes written [itex]\hat{e}_r[/itex]) is the radial unit vector.

Different authors use different notations.
 
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yes, I've heard of it.. I now need to find the normal vector first... how can I do that...
 


Start by drawing a sketch of the surface, you should see that the outward normal to the surface is the same as the outward normal of the curve z=9-x^2. Parameterize that curve (I suggest using x=t) and find the tangent and normal in the usual ways.
 

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