Stopping Distance for 25000kg Train Traveling at 18m/s: Conductor's Dilemma

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SUMMARY

The discussion centers on calculating the stopping distance of a 25,000 kg train traveling at 18 m/s when faced with an obstacle, specifically a cat, located 45 meters ahead. The train's brakes can exert a frictional force of 75,000 Newtons. Using the formula for stopping distance, which incorporates mass, initial velocity, and braking force, it is established that the conductor must determine if the stopping distance is less than or equal to 45 meters to avoid a collision.

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  • Understanding of Newton's Second Law of Motion
  • Knowledge of basic kinematics
  • Familiarity with the concept of frictional force
  • Ability to apply equations of motion in real-world scenarios
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  • Calculate stopping distance using the formula: stopping distance = (initial velocity^2) / (2 * (frictional force / mass))
  • Explore the implications of varying mass and frictional force on stopping distance
  • Research real-world applications of braking systems in trains
  • Investigate safety protocols for train conductors in emergency situations
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Engineers, physics students, train conductors, and safety analysts interested in understanding the dynamics of train braking and collision avoidance.

xbebegirlx
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a 25000kg train travel down a track at 18m/s. a cat wander onto the track 45m ahead of train, causing the conductor to slam on the brakes. The train skids to a stop. If the brakes can provide 75,000 Newtons of friction, will the conductor have enough stopping distance to avoid hitting the cat?
 
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Hi xbebegirlx, welcome to PF.
Please go through the rules of PF. You have to show your attempts. At least the relevant equations which can be used in the given problem. You must know on which topic the problem is based. We are here to help you. But we can't the problem for you.
 

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