Strategies for Computing Limits Involving Square Roots and Rational Expressions

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The discussion centers on computing the limit of a summation involving square roots and rational expressions. Participants suggest that isolating the variable i within the summation is not feasible, and instead recommend using integration techniques to evaluate the limit. A specific integral, likely related to the area under a curve, is mentioned as a more straightforward approach. The conversation emphasizes that clever approximations may be necessary for direct limit calculations, which could exceed typical calculus II expectations. Ultimately, the focus is on leveraging integral calculus to simplify the limit evaluation process.
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I'm trying to isolate the i variable in this formula. Thanks for any help.

\lim_{n->infinity}\frac{5}{n}\sum_{i=1}^{n}\sqrt{25-\frac{5i^2}{n^2}}
 
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i is a dummy variable for the summation. What do you mean by "isolate"? Also by inspection, it looks like the limit can be gotten by integral from 0 to 1 of 5(25-5x2)1/2.
 
I'm trying to get i to be by itself inside the summation sign but I don't know how to get rid of that square root.
 
:confused:
I don't understand the last post. But if you want only to calculate the limit, mathman gave you the right direction (integrate)
 
You won't be able to isolate i in this equation.

To compute that limit directly, I think you'll pretty much have to do some sort of clever approximation, and prove the error in the approximation goes to zero as n goes to infinity. Actually carrying out this programme is well beyond what would be expected in a calc II Class.

This limit presumably comes from some sort of integral, probably \int_0^5 \sqrt{5^2 - x^2} \, dx. There's a clever choice of partition for which the Riemann sum is much easier to compute, but as mathman was trying to hint, there's a much easier way to come up with the value of this integral...
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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