Stress on 25 micron Fiber Under Elongation Load

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benndamann33
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This doesn't seem particularly hard, thought it was simply an F/A situation but apparently not. A fiber with a diameter of 25 micro meters is subjected to elongation load of 25 g along the fiber axis. What is the stress on the fiber? Is the applied stress a shear or a tensiles stress. I said it was a tensil stress and went on to compute F/A. F was .025Kg * 9.8N and A was simply ((25*10^-6)/2)^2*pi. The resultant stress was 500 MPa. The correct answer is .125 MPa. Any suggestions??!
 
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yeah I'm going with text is wrong, .125 is found by not dividing the radius by 2 and then dividing by a factor of 1000...haha only thing I could find out, but thank you!