Deducing what the area under the stress-strain curve shows.
There are four option in the attached image. I can discount work done by considering the units. The remaining ones seem plausible, but only one is true.
stress = force / area; strain = proportional extension in length
The Attempt at a Solution
stress units are N / m2
strain units are unitless
The units of the area could be N / m2 but Nm / m3 units are also consistent. Work done / Volume variants seem plausible.
If the line was y = mx then then area underneath would be (1/2)mx2. Here we have stress = young's modulus . strain.
I would have thought the area under the line is (1/2) young's modulus . strain2. Not sure that helps.