Stress Tensor Homework: Finding Traction Vector

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Homework Help Overview

The discussion revolves around the concept of traction vectors derived from a stress tensor in the context of mechanics. The original poster is attempting to find a traction vector by using a normal vector that forms equal angles with the coordinate axes.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to determine a traction vector by dotting a normal vector with the stress tensor, expressing confusion over the results not matching the provided traction vectors. Other participants question the assumption that only three traction vectors exist and discuss the implications of using a non-basis normal vector.

Discussion Status

Participants are exploring different interpretations of the problem, with some providing insights into the nature of traction vectors and their relation to the stress tensor. There is acknowledgment of the complexity of the problem, and guidance has been offered regarding the relationship between the rows of the stress tensor and the traction vectors.

Contextual Notes

There is mention of the timing of responses, with some participants noting that many students may be on break, which could affect the speed of replies. The original poster expresses concern about the lack of responses, indicating a desire for clarification on the problem statement.

racnna
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Homework Statement


http://img842.imageshack.us/img842/9577/stresstensor.png

Homework Equations


'traction vectors' are just the rows of the stress tensor. that is, the first row of the stress tensor(the i-component of the tensor) is the first traction vector, second row is the second,etc.
traction vector equation is
<b>t<sub>n</sub></b>=<b>n</b> dot <b>T</b>


The Attempt at a Solution



I was trying to find a surface whose normal vector forms the same angle with the three coordinate axes. and then dot this normal vector with the stress tensor in order to determine the traction vector. but the result i get is not any of the three given traction vectors
 
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uh oh...58 views and no replies? i am positive you experts have encountered stuff like this...there are much harder problems on this forum! if it helps, please IGNORE my post about relevant equations and just focus on the problem statement

alright...and let me know if there's any confusion about the problem statement
 
racnna said:
I was trying to find a surface whose normal vector forms the same angle with the three coordinate axes. and then dot this normal vector with the stress tensor in order to determine the traction vector. but the result i get is not any of the three given traction vectors

What result do you get? Why do you think there are only 3 traction vectors?

racnna said:
uh oh...58 views and no replies? i am positive you experts have encountered stuff like this...there are much harder problems on this forum! if it helps, please IGNORE my post about relevant equations and just focus on the problem statement

alright...and let me know if there's any confusion about the problem statement

Please exercise some patience. Most students are still on summer break, and homework helpers do not check the forum as frequently. None of us are paid to help you, it is just something we choose to do in our free time.
 
woah easy there. I didnt mean to offend you. I just got worried because there were so many views and no replies so i thought there was a problem with the way the problem is worded.

I think there's an infinite number of traction vectors?...but the rows of the Tensor should give you three traction vectors?

i used the unit vector \frac {1}{√3}, \frac {1}{√3}, \frac {1}{√3} and dotted this with the stress tensor to get the traction vector they are asking for. Is that correct?
 
racnna said:
I think there's an infinite number of traction vectors?...but the rows of the Tensor should give you three traction vectors?

Yes. The 3 rows of the stress tensor correspond to traction vectors for surfaces normal to one of the 3 basis coordinates. Your surface normal isn't directed along any of the basis vectors (i, j, k) though, so there is no reason to expect the traction vector to be one of those rows.

i used the unit vector \frac {1}{√3}, \frac {1}{√3}, \frac {1}{√3} and dotted this with the stress tensor to get the traction vector they are asking for. Is that correct?

Yes. :approve:
 
Aha! thanks so much gabba
 

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