Strong Induction problem related to combinatorics

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Homework Help Overview

The discussion revolves around the relationship between the number of subsets of an n-element set and the number of subsets of an (n-1)-element set, specifically exploring the proof of this relationship using strong induction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to establish that the number of subsets of an n-element set is 2 times the number of subsets of an (n-1)-element set, expressing uncertainty about the proof process and the use of strong induction.
  • Some participants suggest using a bijection approach instead of induction, raising questions about the completeness of the proof for all n.
  • There is a discussion about dividing the subsets into two categories based on the inclusion of the nth element, which leads to a proposed bijection.

Discussion Status

The discussion is active, with participants exploring different methods of proof. Some guidance has been offered regarding the use of a bijection, and there is an acknowledgment of the original poster's approach, though uncertainty remains about proving the statement for all n.

Contextual Notes

The original poster mentions confusion regarding the material in their textbook and expresses a desire for assistance in formulating the correct inductive hypothesis.

starcoast
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Homework Statement



How is the number of subsets of an n-element set related to the number of subsets of an (n-1) element set? Prove that you are correct.

Homework Equations





The Attempt at a Solution


So, clearly the the number of subsets in an n element set is 2^{n}. So the number of subsets of an n-element set is 2*(the number of subsets of an n-1 element set). But I'm having trouble proving it. I'm pretty sure strong induction is what I need to use here, but we haven't talked about it in class and the material in the book is confusing, with little explanation (our book is mostly learn-on-your-own examples). If someone could walk me through the proof, or at least help me get to the correct inductive hypothesis, I would be really grateful.
 
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welcome to pf!

hi starcoast! welcome to pf! :smile:

hint: split the set of subsets of an n-element set into two :wink:
 


tiny-tim said:
hi starcoast! welcome to pf! :smile:

hint: split the set of subsets of an n-element set into two :wink:

Okay, I used that bijection instead of induction, but something about it doesn't feel like I proved it for all n. How does this look?

We divide the subsets of a given n-element set T into two sets: the set of subsets that contain the nth element in the set, S, and the set of subsets that do not contain the nth element in the set, P. We find a bijection between the two sets: set S can be constructed from set P by adding the nth term of set T to the end of each term in set P. This bijection indicates that by adding 1 to n, we double the size of the set of subsets. In other words, Sn = 2 * Sn-1
 
starcoast said:
Okay, I used that bijection instead of induction, but something about it doesn't feel like I proved it for all n. How does this look?

looks ok to me …

you've proved it for any n :smile:
 

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