Struggling with Algebra Radicals: What's the Right Approach?

[Counterstrike]

Homework Statement

This is the problem. I seem to be having a hard time removing the radicals.
The answer should be 12/5. I have no idea how to get there. I am just trying to learn how to handle a situation like this, so I can be prepared in the future.

2x*(4x-1)^-1/2 - 3sqrt(4-x) = 0

The Attempt at a Solution

I've tried flipping the negative exponent into a fraction and then combining it into one fraction. I tried to directly remove the radicals by squaring everything, but somewhere I must be doing something wrong.

Any hints to the procedures on how to solve this?

 

[SammyS]

Add $3(\sqrt{4-x}\,)$ to both sides.

Multiply both sides by $\sqrt{4x-1}\,.$

Square both sides.

After doing some algebra, you will have a quadratic equation

 

[symbolipoint]

2x*(4x-1)^-1/2 - 3sqrt(4-x) = 0

$\frac{2x}{\sqrt{4x-1}} - 3\sqrt{4-x}=0$
$\frac{2x}{\sqrt{4x-1}} = 3\sqrt{4-x}$
Square both sides.
...

 

[Counterstrike]

Just replying to thank you for your swift response! Much appreciated. Yes, that did help me quite a bit. In the future, I will be including more info on how I approached the problem. I was really tired that night.