The problem involves a student librarian lifting and carrying a book, specifically calculating the work done on the book during this process. The context includes forces, distances, and the application of the work formula in a physics setting.
The discussion is ongoing, with participants exploring the correct interpretation of the work formula. Some guidance has been provided regarding the direction of force and displacement, but there is no explicit consensus on the final approach to the problem.
Participants are navigating the nuances of the work formula, particularly in relation to the angles involved in force and displacement. There is an emphasis on understanding the components of force that contribute to work done.
Your formula for work is not quite correct. Only the component of the force in the direction of the displacement does work.For example, to find our how much work is done in carrying the book 8.0 meters to the stacks, answer the following question: How much force acts in the direction of the 8 meter displacement?Iceclover said:Homework Statement
a student librarian picks up a 22N book from the floor to a height of 1.25m. He carries the book 8.0m to the stacks and places the book on a shelf that is 1.35m high. How much work does he do on the book
Homework Equations
W=Fd
The Attempt at a Solution
Am i just supposed to add up all the distances and then use my W=Fd formula?
W = Fdcos\thetaIceclover said:what is the correct formula for work then?