Studying for exam- telescope problem (help )

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Homework Help Overview

The problem involves determining the diameter of an optical telescope required to resolve a lunar lander that is 3 meters across, located on the moon's surface approximately 3.8e8 meters away. The context is rooted in optics and angular resolution.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the formula theta=1.22lamda/d for angular resolution and question how to apply it to the problem. There is a suggestion to assume a typical wavelength for lambda and to calculate the angular separation based on the size of the lander and its distance.

Discussion Status

The discussion is progressing with participants clarifying concepts related to angular separation and the application of the formula. Some guidance has been offered regarding the assumptions needed for the calculations.

Contextual Notes

Participants are considering typical values for the wavelength of light in the visible spectrum and how these relate to the problem's parameters. There is an emphasis on understanding the relationship between the size of the object and its distance for resolving power.

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studying for exam- telescope problem (help!)

Homework Statement



What diameter optical telescope on the Earth would you need to resolve a lunar lander 3 m across on the surface of the moon 3.8e8m away?

Homework Equations





The Attempt at a Solution


the only thing I can think of is to use theta=1.22lamda/d... but what do I do with it? help!
 
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You need to assume a typical value for lambda. A wavelength in the visible spectrum.
d is the diameter you need to calculate.
theta is the angular separation of two points that can just be resolved.
What is the angular separation of those two points on the moon?
 


oh! that makes sense. so is the angular separation the size of the lander divided by the distance to it?
 


That should work fine.

(Welcome to Physics Forums, by the way)
 


yay! thank you!
 

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