# Stuntman jumping 2D kinematics.

1. Sep 8, 2009

### CandyApples

1. The problem statement, all variables and given/known data
A stuntman is jumping from building A to building B. His flight lasts 1s. He leaves point A with a speed of Vo at an angle of 30 degrees above horizontal. Building B is .9m shorter than building A. What horizontal distance was covered by the stuntman given he makes it to the very edge of building B? What was the maximum height with respect to the starting point attained by the stuntman?

2. Relevant equations
Displacement and velocity kinematic equations.

3. The attempt at a solution
displacement x= cos(30)*Vo*1s
displacement y= sin(30)*vo+.5(-9.8)(1)-.9m

I know that somehow i need to find Vo from the Y data then plug it into the x displacement equation but i am not sure how this is going to be possible with the given information.

2. Sep 9, 2009

### method_man

Consider building A as a xy origin, and building B as a final point. When you look at the formula for vertical displacement y=-1/2*g*t2+vy*t, you know the time t and position y at that time t. Take under consideration that y is negative (-9).