Subgroup of D_n: Proving <f> Not Normal

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SUMMARY

The discussion centers on proving that the subgroup generated by a reflection f in the dihedral group D_n is not normal. The subgroup consists of the elements {e, f}, where e is the identity. The key argument is to demonstrate that for any element g in D_n, the conjugate g(r^kf)g^-1 does not belong to . A suggestion is made to clarify the notation and ensure proper mathematical communication for better understanding.

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rapple
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Homework Statement



S.T <f> is not normal. where f is a reflection

Homework Equations


<f>={e,r^0 f, r^1f,r^2f,..}
WTS For any g in D-n, g(r^kf)g^-1 Not In <F>

The Attempt at a Solution


Elements of D-n are r^k, r^kf
For r^k, (r^k)(r^if)(r^-k) is in <f>.

So I am stuck
 
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rapple said:
WTS For any g in D-n, g(r^kf)g^-1 Not In <F>

No. You want to show there exists such a g. Just find one.
 
The subgroup generated by f, which is what <f> usually means, is just {e,f} with e the identity. What you wrote is in fact all of D_n. You probably should write in proper sentences so that everyone is sure what you mean (i.e. no abbreviations that might not be universally understood) - reading mathematics is hard at the best of times, so please help us out and make it as easy as possible.
 

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