Subgroup proof - is this even true?

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SUMMARY

The discussion centers on the proof that a group G cannot have a subgroup H with |H| = n - 1, where n = |G| > 2. Participants provide counter-examples using the multiplicative group of real numbers R and its subgroup R+, as well as the additive group of integers Z and its subgroup of even integers. The consensus is that the statement is trivial for finite groups, as the definition of |H| = n - 1 implies that G must be finite.

PREREQUISITES
  • Understanding of group theory concepts, specifically subgroup definitions.
  • Familiarity with finite and infinite groups.
  • Knowledge of the properties of the multiplicative group R and the additive group Z.
  • Basic comprehension of group order and its implications.
NEXT STEPS
  • Study the properties of finite groups in group theory.
  • Learn about Lagrange's theorem and its implications for subgroup orders.
  • Explore counter-examples in group theory to solidify understanding of subgroup properties.
  • Investigate the differences between finite and infinite groups in more detail.
USEFUL FOR

This discussion is beneficial for students of abstract algebra, particularly those studying group theory, as well as educators seeking to clarify subgroup properties and their implications in both finite and infinite contexts.

1MileCrash
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Homework Statement



Prove that G cannot have a subgroup H with |H| = n - 1, where n = |G| > 2.

Homework Equations





The Attempt at a Solution



Counter-example, the multiplicative group R and its subgroup, multiplicative group R+. Or, the additive group Z, and its subgroup of integer multiples of 2. What am I missing here? I think this is trivial for finite groups, but they don't say finite groups, they don't say anything.
 
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1MileCrash said:

Homework Statement



Prove that G cannot have a subgroup H with |H| = n - 1, where n = |G| > 2.

Homework Equations





The Attempt at a Solution



Counter-example, the multiplicative group R and its subgroup, multiplicative group R+. Or, the additive group Z, and its subgroup of integer multiples of 2. What am I missing here? I think this is trivial for finite groups, but they don't say finite groups, they don't say anything.

Saying n=|G| implies that the group is finite and has order n. Otherwise |H| = n - 1 wouldn't make much sense.
 
OK

Thanks
 

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