Subspace Intersection Problem: Proving W1 and W2 in R^n

  • Thread starter Thread starter mlarson9000
  • Start date Start date
  • Tags Tags
    Subspace
Click For Summary

Homework Help Overview

The problem involves proving that the intersection of two subspaces, W1 and W2, in R^n is also a subspace. Participants are exploring the properties of vector spaces and the implications of closure under addition and scalar multiplication.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants attempt to reason that since W1 and W2 are subspaces closed under addition and scalar multiplication, their intersection W must also exhibit these properties. Others question how to articulate this reasoning formally in mathematical terms.

Discussion Status

The discussion is ongoing, with participants exploring the implications of closure properties and seeking to express their reasoning in a formal mathematical context. Guidance has been offered on how to structure the proof, but no consensus has been reached on the final argument.

Contextual Notes

Participants express uncertainty about how to generalize their understanding beyond specific cases in R^2 and R^3, indicating a need for clarity on the definitions and properties of subspaces.

mlarson9000
Messages
46
Reaction score
0

Homework Statement



Let W1 and W2 be two subspaces of R^n. Prove that their intersection is also a subspace.

Homework Equations





The Attempt at a Solution



I know that in R^2 and R^3 the intersection would be the origin, which would be the zero vector, which would be a subspace, but I don't know how to make a general argument about this.
 
Physics news on Phys.org
Let W be the intersection of W1 and W2. Is the vector space W closed under addition and scalar multiplication?
 
VeeEight said:
Let W be the intersection of W1 and W2. Is the vector space W closed under addition and scalar multiplication?

Wouldn't it have to be? If W is in both W1 and W2, which are both subspaces and therefore closed under addition and scalar multiplication, wouldn't W be also? If so, I still don't know exactly how to say that in Math speak.
 
mlarson9000 said:
Wouldn't it have to be?
Well, if not, you're going to have a tough time proving it.
mlarson9000 said:
If W is in both W1 and W2, which are both subspaces and therefore closed under addition and scalar multiplication, wouldn't W be also?
Take a couple of arbitrary vectors u1 and u2 in W, and show that their sum is also in W. Then take an arbitrary scalar s, and show that su1 is in W. That's how you would do it it "math speak."
mlarson9000 said:
If so, I still don't know exactly how to say that in Math speak.
 
mlarson9000 said:
Wouldn't it have to be? If W is in both W1 and W2, which are both subspaces and therefore closed under addition and scalar multiplication, wouldn't W be also? If so, I still don't know exactly how to say that in Math speak.
Suppose u and v are in W. Then u and v are both is W1 and, since W1 is a subspace, u+ v is in W1. Also u and v are both in W2 ...
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K