(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Let V =C(complex numbers). Prove that the onlyC-subspaces of V are V itself and {0}.

2. Relevant equations

3. The attempt at a solution

Well this problem has me confused since I have clearly found a complex subspace for example all the complex numbers of the form

{a+ib : a=b}

are closed under addition and scalar multiplication, hence it is a subspace. So if I've found another subspace in the complex numbers how can its only subspace be itself and the empty set?

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# Homework Help: Subspace of a Vector Space over Complex Numbers Proof.

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