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Successive dilution problems
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[QUOTE="Benzoate, post: 1418926, member: 80744"] [h2]Homework Statement [/h2] The following successive dilutions are applied to a stock solution that is 5.60 M sucrose * Solution A = 46.0 mL of the stock sollution is diluted to 116 mL * Solution B = 58.0 mL of Solution A is diluted to 248 mL * Solution C = 87.0 mL of Solution B is diluted to 287 mL What is the concentration of sucrose in solution C? C(final)=C(initial)*(V(1)/V(2))*(V(3)/V(4)) * (V(5)/V(6)) [h2]Homework Equations[/h2] C(final)=C(initial)*(V(1)/V(2))*(V(3)/V(4)) * (V(5)/V(6)) [h2]The Attempt at a Solution[/h2] C(final) = (5.60 M)*(46 mL/116 mL)*(58 mL/248 mL)*(87 mL/287 mL) C(final)= .157 M Is that how I would calculate the final concentration? [/QUOTE]
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Successive dilution problems
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