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Successive dilution problems

  1. Sep 4, 2007 #1
    1. The problem statement, all variables and given/known data
    The following successive dilutions are applied to a stock solution that is 5.60 M sucrose

    * Solution A = 46.0 mL of the stock sollution is diluted to 116 mL
    * Solution B = 58.0 mL of Solution A is diluted to 248 mL
    * Solution C = 87.0 mL of Solution B is diluted to 287 mL

    What is the concentration of sucrose in solution C?
    C(final)=C(initial)*(V(1)/V(2))*(V(3)/V(4)) * (V(5)/V(6))

    2. Relevant equations
    C(final)=C(initial)*(V(1)/V(2))*(V(3)/V(4)) * (V(5)/V(6))

    3. The attempt at a solution

    C(final) = (5.60 M)*(46 mL/116 mL)*(58 mL/248 mL)*(87 mL/287 mL)
    C(final)= .157 M

    Is that how I would calculate the final concentration?
  2. jcsd
  3. Nov 23, 2016 #2


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    Looks good.
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