Hi, roots problem again x(.(adsbygoogle = window.adsbygoogle || []).push({});

The roots of the equation x^{2}+px + 1 = 0 areaandb. If one of the roots of the equation x^{2}+ qx + 1 = 0 isa^{3}, prove that the other root isb^{3}. [Done]

Without solving any equation, show that q = p(p^{2}- 3). Obtain the quadratic equation with rootsa^{9}andb^{9}, giving the coefficients of x in terms of q.

Can't solve the last one, which isa^{9}andb^{9}. I got

x^{2}+ (q^{3}-3p)x + 1.

it's suppose to be x^2 + [q^{2}(q -3)]x + 1.

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# Sum of roots, product of roots

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