Sum of the fourth powers of the first n positive integers

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SUMMARY

The formula for the sum of the fourth powers of the first n positive integers is given by S(N) = (1/30)(N+1)(N)(2N+1)((3N^2)+3N-1). To prove this formula, one must use mathematical induction. The inductive step involves demonstrating that S(N+1) - S(N) equals (N+1)^4, confirming the validity of the formula. This approach is essential for establishing the correctness of the derived formula.

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  • Knowledge of polynomial expressions
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  • Explore the derivation of the sum of cubes formula
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Students studying mathematics, particularly those focusing on algebra and calculus, as well as educators looking for effective teaching methods for mathematical induction and summation techniques.

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Homework Statement



Find a formula fo the sum of the fourth powers of the first n positive integers

n
∑ i^4
(i=1)


Justify your work using mathematical induction

Homework Equations



so i know the formula for the sum of the cubes of the first n positive integers

k=n+1
∑ = (1^3)+(2^3)+(3^3)+...+(n^3)+((n+1)^3)= {((n+1)^2)((n+2)^2)} / (4)
k=1

I was wondering what was the proof for the sum of the quartic of the first n positive integers

The Attempt at a Solution



This is actually what I started working out and I don't know whether it is right

N
∑ i^4 = (1/30)(N+1)(N)(2N+1)((3N^2)+3N-1)
i=1
 
Last edited:
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Sure, that's right. I know it's right because I looked it up. Just like you, probably. The problem is that you have to prove it's right. Call your sum S(N). Then the inductive step (after you shown it's true for N=1) is to show S(N+1)-S(N)=(N+1)^4. Do you see why? If you see why, that's the important part.
 
Last edited:

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