Sum of the Values of X, Exponential Equation

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    Exponential Sum
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Homework Help Overview

The problem involves solving the exponential equation (4x)^(1 + log(base 2) (x)) = 8(x^3) and determining the sum of the values of x that satisfy this equation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various approaches to simplifying the equation, including taking logarithms and checking specific values of x. There is mention of the potential number of solutions and how to find them.

Discussion Status

Some participants have offered guidance on taking logarithms to simplify the equation. There are ongoing questions about the number of solutions and specific values of x that may satisfy the equation, with no explicit consensus reached.

Contextual Notes

Participants are exploring the implications of the equation and the constraints of the problem, including the requirement to use specific methods or approaches in their solutions.

wiraimperia
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Homework Statement


(4x)^(1 + log(base 2) (x)) = 8(x^3)
What is the sum of the values of x that fullfill that equation?
A) 2.5
B) 2.0
C) 1.5
D) 1.0
E) 0.5

Homework Equations


Use the exponential equation only and make the lower one (exponented) 1.

The Attempt at a Solution


(4x) = (2 x^(1/2))^2
8(x^3) = (2x)^3
If I insert x = (1/4) to make 4x = 1 it doesn't fulfill the equation..
So does x = (1/2)..
I cannot simplify the exponential equation... Any assistance please?
 
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hi wiraimperia! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)

for any number n, what is nlog2(x) ? :wink:
 
4x(4x)^{\log_2x} = 8x^3
... how many values of x satisfy the equation?

I'd recheck for x=1/2 ...
 
Last edited:
I mean if it has 2 solutions, then we are asked X1 + X2, if it has 3, then X1 + X2 + X3, and so on...
 
wiraimperia said:
I cannot simplify the exponential equation... Any assistance please?

Try to take the logarithm of both sides.

ehild
 
for any number m, what is (2m)log2(x) ? :wink:
 
wiraimperia said:
I mean if it has 2 solutions, then we are asked X1 + X2, if it has 3, then X1 + X2 + X3, and so on...
Is there any way you can figure out how many solutions it is likely to have?
Have you rechecked if x=1/2 is a solution? Personally I managed it by systematic guesswork using the list of possible solutions ... but I've had practice.

Have you tried any of the other suggestions and hints? They are all good.

Is there a particular method you are supposed to use or can we throw anything we like at the problem? eg. there's always brute-force methods like plotting the curves to get ballpark figures and then using Newton/Raphson ...
 
Taking logarithm on both sides with base 2, you get:
(1+log_2 x)log_2(4x)=3+3log_2 x

It is easy to solve now. :smile:
 

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