Super ball Acceleration question

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SUMMARY

The discussion focuses on calculating the average acceleration of a Super Ball that rebounds off a wall. The ball has a mass of 45.0 g, initial velocity of 30.0 m/s, and rebounds at 17.0 m/s after 4.50 ms of contact with the wall. The correct formula for average acceleration is derived from the change in velocity divided by the time interval, taking into account the direction of the velocities as vector quantities. The final calculation confirms that the average acceleration is indeed based on the change in velocity from -30.0 m/s to 17.0 m/s over the specified time.

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A 45.0 g Super Ball traveling at 30.0 m/s bounces off a brick wall and rebounds at 17.0 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 4.50 ms, what is the magnitude of the average acceleration of the ball during this time interval? (Note: 1 ms = 10-3 s.)


please explain...i don't get it!
 
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As you have been told previously, you must show some effort in solving the question yourself before we can help you.
 
I know everyone doesn't have natural talent in physics but just look at the basics first.

Im 15 doing high school physics and i can get it.

First list data, then see relevant equations should be pretty basic from there.

Always do that with all questions,, list data,, look for equations,, sometimes it also helps to draw diagrams if that makes it clearer for you.
 
well i know that the average acceleration equation is the change of velocity/change in time

so i thought it would be

17m/s-30m/s
____________

.0045 s


but i can't seem to get the right answer..i think I am missing something?
 
velocities are vector quantities.. so 17-(-30) because the ball is changing direction
then divide by the time
 
What is the correct answer?
 

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