Calculating Average Acceleration of a Bouncing Super Ball

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SUMMARY

The average acceleration of a 45.0-g Super Ball, which rebounds from a brick wall after traveling at 30.0 m/s and rebounding at 20.5 m/s, is calculated to be 13600 m/s². This calculation is based on the change in velocity over the time interval of 3.70 ms during which the ball is in contact with the wall. The confusion regarding the sign of acceleration arises from the interpretation of velocity changes, where the ball's deceleration upon impact is followed by an increase in velocity in the opposite direction.

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  • Understanding of basic physics concepts such as velocity and acceleration
  • Familiarity with the formula for average acceleration: (final velocity - initial velocity) / time
  • Knowledge of units of measurement, specifically meters per second (m/s) and milliseconds (ms)
  • Ability to convert mass from grams to kilograms for calculations involving force
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  • Explore the effects of elastic collisions on objects
  • Investigate the use of high-speed cameras in motion analysis
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MG5
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A 45.0-g Super Ball traveling at 30.0 m/s bounces off a brick wall and rebounds at 20.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.70 ms, what is the magnitude of the average acceleration of the ball during this time interval?

Apparently the answer is 13600 m/s squared.

No idea how to get that though.
 
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What is average acceleration?
 
MG5 said:
A 45.0-g Super Ball traveling at 30.0 m/s bounces off a brick wall and rebounds at 20.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.70 ms, what is the magnitude of the average acceleration of the ball during this time interval?

Apparently the answer is 13600 m/s squared.

No idea how to get that though.

I'm a bit sleepy at the moment and might have overlooked something, but it doesn't make sense that the acceleration is positive when the ball slows down by 9,5m/s..
 

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