- 42,640
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Right. The 2m-n form is the useful one here.Bunny-chan said:Oh.
4m^2 + n^2 = (2m + n)^2 - 4mn or (2m - n)^2 + 4mn
Write the second equation in post #47 using that.
Can you get from that an upper bound on a?
Right. The 2m-n form is the useful one here.Bunny-chan said:Oh.
4m^2 + n^2 = (2m + n)^2 - 4mn or (2m - n)^2 + 4mn
Would that be \frac{1}{4}?haruspex said:Right. The 2m-n form is the useful one here.
Write the second equation in post #47 using that.
Can you get from that an upper bound on a?
Yes.Bunny-chan said:Would that be \frac{1}{4}?
Excellent! And we have 0 as infimum?haruspex said:Yes.
As far as I am aware, there is not universal agreement on whether ℕ includes 0. What have you been taught?Bunny-chan said:Excellent! And we have 0 as infimum?
Oh, I've forgot that. Particularly my professor doesn't include it either.haruspex said:As far as I am aware, there is not universal agreement on whether ℕ includes 0. What have you been taught?
Maybe it does not matter. If we exclude 0, can you still get 0 as infimum?Bunny-chan said:Oh, I've forgot that. Particularly my professor doesn't include it either.
It's true that we can never get any value equal to zero, but the infimum doesn't need to be contained in the set, as you said. But I'm not very sure how to verify if 0 is the infimum.haruspex said:Maybe it does not matter. If we exclude 0, can you still get 0 as infimum?
Consider very unequal values of m, n.Bunny-chan said:It's true that we can never get any value equal to zero, but the infimum doesn't need to be contained in the set, as you said. But I'm not very sure how to verify if 0 is the infimum.
The values indeed get more and more close to zero.haruspex said:Consider very unequal values of m, n.
Right.Bunny-chan said:The values indeed get more and more close to zero.
Thank you for this loooong aid!haruspex said:Right.