Surface area by revolving a curve problem, help

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SUMMARY

The discussion centers on calculating the surface area generated by revolving the curve defined by the equation y=sqrt(4-x^2) around the x-axis, specifically for the interval -1 < x < 1. Participants emphasize the importance of setting up the integral correctly to solve the problem. The community encourages users to demonstrate their understanding by attempting to set up the integral before seeking further assistance.

PREREQUISITES
  • Understanding of surface area calculations for revolved curves
  • Familiarity with integral calculus
  • Knowledge of the equation y=sqrt(4-x^2)
  • Basic concepts of coordinate systems
NEXT STEPS
  • Study the formula for surface area of revolution: A = 2π ∫[a to b] y * sqrt(1 + (dy/dx)²) dx
  • Practice setting up integrals for different curves and axes of rotation
  • Explore the properties of the function y=sqrt(4-x^2) and its geometric implications
  • Learn about the application of definite integrals in calculating area and volume
USEFUL FOR

Students studying calculus, educators teaching integral calculus, and anyone interested in mathematical modeling of surfaces of revolution.

Waggattack
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Surface area by revolving a curve problem, help!

can someone show me how to solve for the surface area when rotating y=sqrt(4-x^2) around the x-axis from -1 < x < 1.

shows the steps please!
thanks
 
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Waggattack said:
can someone show me how to solve for the surface area when rotating y=sqrt(4-x^2) around the x-axis from -1 < x < 1.

shows the steps please!
thanks

Welcome to the PF. We do not do your schoolwork for you. What coordinate system do you think is best for this problem? Why? Now show us how you would try to set up the integral, and we can comment if you are having problems with the work that you post for us...
 

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