1. I am suppose to find the surface area of the curve y=sqrt(4-x^2) from -1 to 1 when it is revolving around the x-axis. 2. Relevant equations: S= 2PIf(x)sqrt(1+(dy/dx)^2)dx 3. I found the derivative to be -x(4-x^2)^-1/2 and then squared it so the problem is 2Pi -1[tex]\int[/tex]1 sqrt(4-x^2)sqrt(1+[x^2(4-x^2)] but I have no clue where to go from here.