Surface integrals to calculate the area of this figure

[VVS2000]

Homework Statement

My homework is to find the area of the following figure(leaving those two squares)

Relevant Equations

The distance between those two squares is one unit. Please do tell if the figure is not descriptive enough

I can find the area of the triangles but can't solve the squares for some reason

 

[VVS2000]

Sry for not including the equations section, I don't know how to type integrals here

 

[PeroK]

Sry for not including the equations section, I don't know how to type integrals here

Are you sure you need integration for this?

 

[VVS2000]

Well the assignmet was clear of me using integration

 

[VVS2000]

And the squares are of 1/2 unit length

 

[PeroK]

Well the assignmet was clear of me using integration

You can, course, use integration to calculate the area of a square or a triangle - just for practice.

 

[LCKurtz]

Please post your image right side up.

 

[archaic]

One edge of one square is at $(-0.5, 0)$ while the other square has an edge at $(0.5,0)$, and the total length between them is $1$.
If you can figure out the distance between $(-0.5, 0)$ and $(0.5,0)$, do you think that you can deduce something?

 

[LCKurtz]

I supose all those denominators that look sort of like an $\alpha$ are actually $2$'s.Your figure shows the inner distance between the squares as $1$ unit and the outer distance between them is $\frac 1 2 - (-\frac 1 2) = 1$ so the squares have sides of length $0$, so they aren't there.

 

[berkeman]

Sry for not including the equations section, I don't know how to type integrals here

See the LaTeX tutorial at the top of the page under INFO, Help.