Surface Integrals: Why Dot ds with Normal?

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In surface integrals, the area element ds is dotted with the normal vector to calculate the flux of a vector field A through the surface. This dot product is essential because flux measures only the component of A that is perpendicular to the surface at each point. While other types of surface integrals exist, the specific form discussed focuses on this flux calculation. Understanding this concept clarifies the necessity of the dot product in the integral. The discussion concludes with a resolution to the initial confusion regarding the use of the normal vector.
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Homework Statement


This is not a HW prob. Just a question.
When doing surface integrals, why should the area element ds be dotted with the normal. I don't get it .
\ointA.n ds

Homework Equations





The Attempt at a Solution

 
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likephysics said:

Homework Statement


This is not a HW prob. Just a question.
When doing surface integrals, why should the area element ds be dotted with the normal. I don't get it .
\ointA.n ds

It doesn't have to be, in general. There are other types of surface integrals as well. The type you've listed above is designed to determine the flux of the vector field A through the surface you are integrating over. The dot product is there because, by definition of flux, you are only concerned with the component of A that is perpendicular to the surface at each point on the surface.
 
Ok. Thanks. I can live with it now.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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