Surface volume of 3-sphere with radius of 2 Planck length?

[mitrasoumya]

What is the surface area ("surface volume") of a 3-sphere having a radius of 2 Planck lengths?

Is the product of the Planck's constant, Einstein's proportionality constant and Planck time also equal to this volume?

Does this equivalence signify anything? What does it signify?

 

[Gigaz]

According to wikipedia, the 3-dimensional cubic hyperarea of a 3-sphere of radius r is 2 pi^2 r^3, which should answer your math questions.

 

[mitrasoumya]

According to wikipedia, the 3-dimensional cubic hyperarea of a 3-sphere of radius r is 2 pi^2 r^3, which should answer your math questions.

Is the product of the Planck's constant, Einstein's proportionality constant and Planck time also equal to this volume (i.e. where r=2 Planck lengths)?

Does this equivalence signify anything?

What does it signify?

 

[Vanadium 50]

I see you are still ignoring what people are telling you about the Planck length. There's no magic to it.

Is the product of the Planck's constant, Einstein's proportionality constant and Planck time also equal to this volume (i.e. where r=2 Planck lengths)?

Well, you need to make up your mind what you are trying to say. Area? Volume? r? 2r?

Does this equivalence signify anything?

If you're actually able to get things so the things you are purporting to be equal to actually be equal - something you haven't yet done - you will have proven π = π.

 

[mitrasoumya]

Well, you need to make up your mind what you are trying to say. Area? Volume? r? 2r? .

I'll try to reword that. What I am saying is - the product of Planck's constant, Einstein's proportionality constant and Planck time is equal to the "surface" volume of a 3-sphere having the radius of 2 Planck lengths.

If you're actually able to get things so the things you are purporting to be equal to actually be equal - something you haven't yet done - you will have proven π = π.

I am sorry I could not understand this part.