SUVAT Problems: Why t-x and Not t+x?

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SUMMARY

The discussion clarifies why, in SUVAT problems, the time for an object that begins motion later is expressed as "t-x" rather than "t+x". Specifically, when analyzing the motion of two balls dropped at different times, the first ball's time is denoted as "t", while the second ball, dropped 5 seconds later, is represented as "t-5". This is because the SUVAT equations apply when the first ball is stationary at t = 0, establishing a clear reference point for both objects' motion.

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  • Familiarity with time intervals in motion analysis
  • Concept of relative time measurement in physics
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nokia8650
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When doing SUVAT problems, why does the item which begins motion later given a time "t-x" where x>0. For example, if dropping a ball, and then dropping another ball 5 seconds later, the first ball's time can be expressed as "t" and the second ball's time as "t-5". Why is it not t+5?

Thanks
 
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Hi nokia8650! :smile:

Because the SUVAT formula you're using (I assume) only works if the ball is stationary at t = 0.

Imagine each ball has its own clock, the first showing t1 and the second showing t2.

So t1 = 0 when the first ball starts.

And t2 = 0 when the second ball starts, which of course is when t1 = 5.

So t2 = t1 - 5. :smile:
 
Thanks a lot!
 

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