Undergrad Sylow subgroup of some factor group

Click For Summary
SUMMARY

The discussion centers on the properties of Sylow p-subgroups within the context of finite groups. Specifically, it establishes that if G is a finite group, K is a subgroup of G, and N is a normal subgroup of G, then the quotient group PN/N is indeed a Sylow p-subgroup of the quotient group KN/N. This conclusion is supported by the application of the second isomorphism theorem and the properties of group orders, confirming that p does not divide the index [KN/N:PN/N]. The discussion also highlights the importance of understanding the relationship between subgroup orders and their indices.

PREREQUISITES
  • Understanding of finite group theory
  • Familiarity with Sylow theorems
  • Knowledge of the second isomorphism theorem
  • Basic concepts of group indices and subgroup orders
NEXT STEPS
  • Study the second isomorphism theorem in detail
  • Explore Sylow theorems and their applications in group theory
  • Learn about group actions and their implications on subgroup structures
  • Investigate examples of finite groups and their Sylow subgroups
USEFUL FOR

Mathematicians, particularly those specializing in group theory, educators teaching abstract algebra, and students preparing for advanced studies in algebraic structures will benefit from this discussion.

moont14263
Messages
40
Reaction score
0
Hi. I have the following question:

Let G be a finite group. Let K be a subgroup of G and let N be a normal subgroup of G. Let P be a Sylow p-subgroup of K. Is PN/N is a Sylow p-subgroup of KN/N?

Here is what I think.

Since PN/N \cong P/(P \cap N), then PN/N is a p-subgroup of KN/N.

Now [KN/N:PN/N]=\frac{|KN|}{|N|} \frac{|N|}{|PN|}= \frac{|KN|}{|PN|}= \frac{|K||N|}{|K \cap N|} \frac{|P \cap N|}{|P||N|} = \frac{|K||P \cap N|}{|P||K \cap N|}= [K:P]\frac{|P \cap N|}{|K \cap N|}Since P is a Sylow p-subgroup of K, then p does not divide [K:P]. Also, p does not divide \frac{|P \cap N|}{|K \cap N|} as \frac{|P \cap N|}{|K \cap N|} \leq 1 because P \cap N is a subgroup of K \cap N. Therefore p does not divide [KN/N:PN/N].

Thus PN/N is a Sylow p-subgroup of KN/N.

Am I right?

Thanks in advance
 
Physics news on Phys.org
Looks broadly OK to me. I just have a few questions.
moont14263 said:
Since PN/N \cong P/(P \cap N), then PN/N is a p-subgroup of KN/N.
1. How do we know that ##PN/N## is a ##p##-group?

$$\frac{|KN|}{|PN|}= \frac{|K||N|}{|K \cap N|} \frac{|P \cap N|}{|P||N|}$$
2. This step seems to be doing a number of things, the validity of none of which is obvious to me. Can you justify it? I can get to the RHS from ##[KN/N:PN/N]##, but not by the route shown above. I would use the 2nd isomorphism theorem and the fact that, for finite groups, ##[A:B]= \frac{|A|}{|B|}##.

$$\frac{|K||P \cap N|}{|P||K \cap N|}=[K:P]\frac{|P \cap N|}{|K \cap N|}$$Since P is a Sylow p-subgroup of K, then p does not divide [K:P].
3. You can stop before the equals sign and just observe that, since P is a Sylow p-subgroup of K, p does not divide \frac{|K|}{|P|}, since the multiplicity of ##p## in the order of ##|P|## must equal the multiplicity of ##p## in the order of ##|K|##.
 
You are free to do what you want. But this is a cross-post. Asking the same question at several different sites. This means Bungo and Andrew both worked out an answer. If you believe it is your right to do this, the net result of persistent cross-posting is a strong possibility that folks will skip your posts next time they see them.

I already know I will. Bye.
 
  • Like
Likes Samy_A
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
9
Views
3K