Synchronous Machine Power Angle Confusion

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SUMMARY

A synchronous machine with an armature voltage power angle of 120 degrees operates as a generator. This conclusion is drawn from the relationship between the excitation voltage (Ef) and the terminal voltage (Vt). In this scenario, with Vt at 2300V and Ef at 3450V, the machine is supplying power to the infinite bus. The simplified power flow equation, P = (V1V2/x)sin(θ), indicates that the power transfer can be calculated using the given parameters, including the synchronous reactance (Xs) of 0.9 per unit.

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  • Understanding of synchronous machine operation
  • Knowledge of power angle concepts in electrical engineering
  • Familiarity with power flow equations
  • Basic principles of three-phase systems
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  • Study synchronous machine performance under varying power angles
  • Learn about the implications of operating conditions on power factor
  • Research the effects of synchronous reactance on power transfer
  • Explore the concept of infinite bus connections in power systems
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Electrical engineers, power system analysts, students studying synchronous machines, and anyone involved in power generation and distribution systems.

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<B>General Power angle question</B>

If I have a synchronous machine that has an armature voltage with a power angle of 120 degrees, is the machine operating as a motor or a generator and why? I have found conflicting answers to this question and need to straighten this up. For my homework problem, it is a 3-phase 1MVA, 2300V, 60Hz and Xs=0.9pu negligible stator resistance, and connected to an infinite bus. Vt=2300 at 0degrees and Ef=3450 at 120 degrees. Any help would be appreciated. I need to determine the power transfer and power factor and to do this I need to know how the machine is operating.
 
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Connected to an infinite bus via what? You need a finite impedance. The simplified power flow equation is ##P=\frac{V1V2}{x}sin(\theta)##
 

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