MHB Syntax of Sum and Integral Notation: Understanding the Differences

Click For Summary
The discussion clarifies the differences in syntax between integral and summation notation. It highlights that reversing the limits of integration introduces a negative sign, while reversing the limits of summation does not. This distinction arises because integrals represent the net area under a curve, while sums aggregate discrete values without a directional change. The integral is related to Riemann sums, where changing the order affects the sign due to the nature of the interval. Understanding these differences is crucial for proper mathematical notation and interpretation.
OhMyMarkov
Messages
81
Reaction score
0
Hello everyone!

Now this may seem silly to you, but I'm rather interested in syntax on this one:

$\displaystyle \int _a ^b f(x)dx= - \int _b ^a f(x)dx$, but $\displaystyle \Sigma_{n=A} ^B = \Sigma_{n=B} ^A$ i.e. there is no need for a minus sign, is this generally accepted in terms of syntax?

Thank you.
 
Physics news on Phys.org
Yes, it is generally accepted that when you change the order of a subtraction you change the sign of the difference. That does not happen with a sum.

If F is an anti-derivative of f, the \int_a^b f(x)dx= F(b)- F(a), not a sum. That's why you have the change in sign: F(a)- F(b)= -(F(b)- F(a)).

You may be thinking that the integral is a sum. While that is not exactly true, it is true that the integral is the limit of "Riemann" sums. But they will be of the form \sum f(x_i)\Delta x= \Delta x( \sum f(x_i) and swapping a and b changes the sign on \Delta x which changes the sign on the entire expression.
 
Last edited by a moderator:
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
14
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
4K
Replies
4
Views
2K