# Homework Help: Taking the derivative, $d$, of both sides of the equation.

1. Nov 9, 2012

### operationsres

Suppose that $B(t)$ is a Wiener process. Suppose that the following equation is true:

$B(t)(t + \frac13 B(t)) = B(t)^{0.5}$.

I've conjured this equation out of thin air (it's probably not true) to ask the following question. Does the above identity (assuming it's correct) enable us to write the following:

$dB(t)dt + \frac13 dB(t) = dB(t)^{0.5}$

?

2. Nov 9, 2012

### SammyS

Staff Emeritus
In a word, no.

Use the product rule.