Tangent line parallel to a plane

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SUMMARY

The tangent line of the curve defined by the parametric equations x=t, y=t², z=t³ is parallel to the plane described by the equation x + 2y + z = 0 at the points where the direction vector of the tangent line is perpendicular to the plane's normal vector (1, 2, 1). The direction vector of the tangent line is (1, 2t, 3t²). Setting the dot product of these vectors to zero leads to the equation 3t² + 4t + 1 = 0, which factors to (3t + 1)(t + 1) = 0, yielding solutions t = -1/3 and t = -1.

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jakey
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Hi guys,

I'm stuck with a problem here:

Let a curve be given by the following parametric equations: x=t, y=t^2, z=t^3. At which points is the tangent line (of the curve) parallel to the plane x + 2y + z = 0?

What is the underlying principle behind this?

My thoughts:
The tangent line is parallel to the plane if their normal vectors are colinear. The normal vector of the plane is (1,2,1). Now I'm stuck here.


thanks!
 
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A line is parallel to a plane if the line is perpendicular to the plane's normal.
The direction of the tangent of the curve is: (1,2t,3t^2)
So 1*1+2*2t+1*3t^2=0, 3t^2+4t+1=0, (3t+1)(t+1)=0, t=-1/3 or -1.
 
jakey said:
Hi guys,

I'm stuck with a problem here:

Let a curve be given by the following parametric equations: x=t, y=t^2, z=t^3. At which points is the tangent line (of the curve) parallel to the plane x + 2y + z = 0?

What is the underlying principle behind this?

My thoughts:
The tangent line is parallel to the plane if their normal vectors are colinear. The normal vector of the plane is (1,2,1). Now I'm stuck here.


thanks!
A line does NOT have a "normal vector" (more correctly, there are an infinite number of vectors normal to a line- a line does not have a specific "normal vector").

A line has a direction vector that must be perpendicular to the normal vector of the plane in order that the line be parallel to the plane.
 
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