Tangent/Normal planes, intersections, vector tangent

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SUMMARY

The discussion focuses on finding the normal and tangent planes to the implicit surface defined by the equation x³ + 5y²z - z² + xy = 0 at the point P=(1,-1,0). The normal vector is calculated using n=(fx, fy, -1), resulting in n=(-2, -1, 1). The tangent plane is derived using the equation fx(x-x0) + fy(y-y0) - (z-z0) = 0, yielding the tangent plane 2x + y - z - 1 = 0. For the vector tangential to the curve of intersection with the plane x + z = 1, the correct approach is to take the cross product of the normals of the two surfaces rather than finding the gradient of the tangent vector.

PREREQUISITES
  • Understanding of implicit functions and gradients
  • Familiarity with tangent and normal planes in multivariable calculus
  • Knowledge of vector operations, specifically cross products
  • Proficiency in using partial derivatives to find surface properties
NEXT STEPS
  • Study the method for calculating normals using the gradient of implicit functions
  • Learn about tangent planes and their equations in multivariable calculus
  • Explore vector calculus techniques, particularly cross products of vectors
  • Investigate applications of normal and tangent planes in physics and engineering
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Students and professionals in mathematics, particularly those studying multivariable calculus, as well as engineers and physicists working with surface intersections and vector analysis.

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Homework Statement



Surface (s) given by

x^3*+5*y^2*z-z^2+x*y=0

question ask to find normal and tangent plane to S at the point P=(1,-1,0) then find vector tangential to curve of intersection of S and the plane x+z=1 at point P.

Homework Equations


The Attempt at a Solution



So I started off finding the normal first using n=(fx,fy,-1) which gave me n=(-2,-1,1).

Then proceeding to the tangent plane using the tangent plane equation fx(x-x0)+fy(y-y0)-(z-z0)=0, which gave me the tangent plane 2*x+y-z-1=0.

Please correct me if my method is right or wrong for the above.

But my real question is the last part of the problem statement, which is to find the vector tangential to the curve intersecting x+z=1.

My guess is to find the gradient of the tangent vector and the gradient of the given curve(x+z=1) and take the cross product of the 2? I have no idea where to begin the last, part, any hint or help would be much appreciated.
 
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Gameowner said:

Homework Statement



Surface (s) given by

x^3*+5*y^2*z-z^2+x*y=0

question ask to find normal and tangent plane to S at the point P=(1,-1,0) then find vector tangential to curve of intersection of S and the plane x+z=1 at point P.



Homework Equations





The Attempt at a Solution



So I started off finding the normal first using n=(fx,fy,-1) which gave me n=(-2,-1,1).


That formula for the normal is for when the equation is in the form z = f(x,y). Your equation is not in that form but in the implicit form f(x,y,z)=0. Use \nabla f.

Then proceeding to the tangent plane using the tangent plane equation fx(x-x0)+fy(y-y0)-(z-z0)=0, which gave me the tangent plane 2*x+y-z-1=0.

Please correct me if my method is right or wrong for the above.

But my real question is the last part of the problem statement, which is to find the vector tangential to the curve intersecting x+z=1.

My guess is to find the gradient of the tangent vector and the gradient of the given curve(x+z=1) and take the cross product of the 2? I have no idea where to begin the last, part, any hint or help would be much appreciated.

The "gradient of the tangent vector" doesn't make any sense. Just cross the normals to the two surfaces.
 

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