- #1
gruba
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Homework Statement
Find tangent line of [itex]y=xe^{\frac{1}{x}}[/itex] at point [itex]x=\alpha[/itex] and it's limit position when [itex]\alpha \rightarrow +\infty[/itex].
Homework Equations
Tangent of [itex]y=f(x)[/itex] at point [itex]M(x_0,f(x_0))[/itex]: [tex]y-y_0=f^{'}(x_0)(x-x_0)[/tex]
The Attempt at a Solution
Applying the above equation for tangent of function,
[tex]y_0=\alpha e^{\frac{1}{\alpha}}, f^{'}(x_0)=\frac{(\alpha-1)e^{\frac{1}{\alpha}}}{\alpha}, x_0=\alpha[/tex]
gives
[tex]y-\alpha e^{\frac{1}{\alpha}}=\frac{(\alpha-1)e^{\frac{1}{\alpha}}}{\alpha}(x-\alpha)[/tex]
How to find limit position of a tangent? Is it a limit of [itex]y[/itex] when [itex]\alpha \rightarrow +\infty[/itex]?