Tangent Plane to f(x,y) = sin(x)cos(y) at (π/3,π/2)

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Discussion Overview

The discussion revolves around finding the equation of the tangent plane to the function f(x,y) = sin(x)cos(y) at the point (π/3, π/2). The focus is on the mathematical reasoning and steps involved in this process, particularly addressing the definition of the function and its implications for determining the tangent plane.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant notes the presence of a z in the definition, questioning its relevance to the problem.
  • Another participant clarifies that the function g is defined as g := z - sin(x)cos(y), indicating that three arguments are needed to specify a value for g.
  • A participant suggests that evaluating the function at the specified point and using that to find the value of Z should be a valid approach.
  • A later reply encourages the participant to attempt the evaluation.

Areas of Agreement / Disagreement

Participants appear to be exploring the problem without a clear consensus on the best approach to take, as they discuss different aspects of the function and its evaluation.

Contextual Notes

There may be limitations related to the assumptions about the function's definition and the need for clarity in specifying the arguments for g.

Feodalherren
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Homework Statement


3a) Find the equation of the tangent plane to the function f(x,y) = sin(x)cos(y) at the point (∏/3,∏/2).


The Attempt at a Solution



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There is quite clearly a z in the definition. What's going on?
 
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It's the way you have g defined. According to the function definition, g := z - sin (x)*cos (y), so you need 3 arguments to specify a value for g.
 
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So if I evaluate the function f(x,y) = sin(x)cos(y) at the point (∏/3,∏/2) and then use that point to find my value of Z it should work?
 
Hey, give it a shot.
 

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