A solid rod of mass M = 1.35 kg and length L = 83 cm is suspended by two strings, each with a length d = 71 cm (see Figure), one at each end of the rod. The string on side B is cut. What is the magnitude of the initial tangential acceleration of end B?
The string on side B is retied and now has only half the length of the string on side A. What now is the magnitude of the initial tangential acceleration of end B if it's cut again?
The Attempt at a Solution
I= (1/3)(1.35)(.83)^2=.31 kg*m^2
a(tangential)= 0.83(35.42)=29.4 m/s^2
I haven't tried b) yet because a) isn't the right answer