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- #1

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- #2

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Its just the magnitude of the vector. It should just be V^2/r.

- #3

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The formula in the previous post is incorrect (that's the magnitude of the *radial* component of the acceleration). What formula are you using for tangential acc?

- #4

Doc Al

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Do you mean

- #5

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- #6

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Im suppose to use At=[dv/dt].

- #7

Doc Al

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OK, whereIm suppose to use At=[dv/dt].

- #8

rcgldr

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Tangental acceleration can still exist on a object traveling in a circular path. The centripetal force just needs to change with respect to speed^{2}, so it always equals m |v|^{2} / r.

The magnitude of tangental acceleration would be the magnitude of angular acceleration times r = |angular acceleration| x r.

The magnitude of tangental acceleration would be the magnitude of angular acceleration times r = |angular acceleration| x r.

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