Tank Volume: Find Volume at 3,000 psi, 80 F

  • Thread starter Thread starter Matt766
  • Start date Start date
  • Tags Tags
    Tank Volume
Click For Summary

Homework Help Overview

The problem involves calculating the interior volume of a scuba diving tank designed to hold 50 standard cubic feet of air at a pressure of 3,000 psi and a temperature of 80°F. The context includes the ideal gas law and considerations regarding unit conversions and pressure types.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the ideal gas law and the necessity of using absolute pressure and temperature. There are questions about unit conversions, particularly between cubic feet and cubic inches, as well as the implications of using Rankine for temperature.

Discussion Status

Participants are actively engaging with the problem, offering corrections and suggestions regarding the calculations. There is a recognition of the need to adjust for absolute pressure and temperature, and some participants are questioning the validity of certain volume calculations. No consensus has been reached on the final volume, and further exploration of the compressibility factor is suggested.

Contextual Notes

There are discussions about the appropriateness of using gage pressure versus absolute pressure, and the potential impact of high pressure on the calculations. The mention of significant figures indicates a concern for precision in the context of the problem.

Matt766
Messages
5
Reaction score
1

Homework Statement


A tank for scuba diving is designed to contain 50 standard cubic feet of air when filled to a pressure of 3,000 pounds per square inch (gage) at an ambient temperature of 80 F. Calculate the interior volume of the tank. A standard cubic foot occupies one cubic foot at T=15 C and 101.3 kPa.

Homework Equations


PV=nRT

The Attempt at a Solution


I used PV/RT = PV/RT . I made sure all the units were correct but the volume I get is way too large.
 
Physics news on Phys.org
Hi Matt766. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Please show your arithmatic so readers can look for mistakes.
 
Last edited by a moderator:
Sure. The underline is for division, and the temperatures go on the left and right of the equal sign respectively. Is there an equation editor or something?

(V * 3,000 lb/in^2) = (14.7 lb/in^2)*(86,414.7 in^3
(539.7 deg R) (518.7 deg R)​

V= 441.4 in^3. This seems weird to me because its such a small volume for a tank.
 
Is Rankine going to work there?

Yes, looks like it can.
 
Last edited:
NascentOxygen said:
Is Rankine going to work there?

Yes, looks like it can.
One point here: the pressure in the tank is supposed to be 3000 psi gage. The ideal gas equation uses absolute pressure and absolute temperature.

Second point: where did 86,414.7 in.3 come from? After all, 1 foot = 12 inches, so 1 ft.3 = ? in.3
 
Didn't convert the right pressure to gage pressure, otherwise I can't see anything amiss. Yes, SK, should go with absolute temps though I see using R doesn't change the result here.
 
I made the tank pressure into an absolute pressure and corrected the volume for the cubic feet. For some reason I added 14.7 to the volume? Thanks haha


(V)*(3,014.7 lb/in^2)
= (86,400 in^3)*(14.7 lb/in^2)
(539.7 deg R) (518.7 deg R)

V=438.4 in^3.
 
From Wikipedia:
An especially common cylinder available at tropical dive resorts is an "aluminium-80" which is an aluminium cylinder with an internal volume of 0.39 cubic feet (11 L) rated to hold about 80 cubic feet (2,300 L) of atmospheric pressure gas at its rated pressure of 3,000 psi (210 bar).
 
NascentOxygen said:
Is Rankine going to work there?

Yes, looks like it can.
Sure.
 
  • #10
Matt766 said:
I made the tank pressure into an absolute pressure and corrected the volume for the cubic feet. For some reason I added 14.7 to the volume? Thanks haha


(V)*(3,014.7 lb/in^2)
= (86,400 in^3)*(14.7 lb/in^2)
(539.7 deg R) (518.7 deg R)

V=438.4 in^3.
In this problem, considering how high the pressure is, we should also have used the compressibility z factor. The pressure is 200 atm., which corresponds to a reduced pressure on the order of about 6. In any event, giving the volume to 4 significant figures is not justified.

Chet
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
15K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K