Taylor Expansion: Wondering Which is Right?

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SUMMARY

The correct Taylor expansion of the function \( f(x, y) = x^2 (3y - 2x^2) - y^2 (1 - y)^2 \) at the point \( (0, 1) \) is given by \( f(x, y) = 3x^2 - (y - 1)^2 + 3x^2 (y - 1) - 2(y - 1)^3 - 2x^4 - (y - 1)^4 \). This conclusion is supported by verification from Wolfram Alpha, which confirms the first expansion as accurate while rejecting the second. Therefore, the first expansion is definitively the correct one.

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  • Understanding of Taylor series expansions in multivariable calculus
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mathmari
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Hey! :o

I want to find the taylor expansion of $f(x, y)=x^2 (3y-2x^2)-y^2 (1-y)^2$ at the point $(0, 1)$ and I got the following:

$$f(x, y)=3x^2-(y-1)^2+3x^2 (y-1)-2 (y-1)^3-2x^4-(y-1)^4$$

but a friend of mine got the following result:

$$f(x, y)=3x^2-(y-1)^2+3x^2 (y-1)+3x (y-1)^2+2(y-1)^3-2x^4-(y-1)^4$$

which of them is the right one?? (Wondering)
 
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mathmari said:
Hey! :o

I want to find the taylor expansion of $f(x, y)=x^2 (3y-2x^2)-y^2 (1-y)^2$ at the point $(0, 1)$ and I got the following:

$$f(x, y)=3x^2-(y-1)^2+3x^2 (y-1)-2 (y-1)^3-2x^4-(y-1)^4$$

but a friend of mine got the following result:

$$f(x, y)=3x^2-(y-1)^2+3x^2 (y-1)+3x (y-1)^2+2(y-1)^3-2x^4-(y-1)^4$$

which of them is the right one?? (Wondering)

Hi! (Wave)

According to Wolfram f(x,y) is equal to your expansion, but it is not equal to the second expansion.

So I believe your expansion is the right one. (Nod)
 
I like Serena said:
Hi! (Wave)

According to Wolfram f(x,y) is equal to your expansion, but it is not equal to the second expansion.

So I believe your expansion is the right one. (Nod)

Great! Thank you! (Smile)
 

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