Taylor Polynomial for f(x)=ln3x

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The discussion focuses on finding the Taylor Polynomial of degree 3 for the function f(x) = ln(3x) centered at a = 1/3. The user has computed the fourth derivative of the function and evaluated these derivatives at x = 1/3. They express uncertainty regarding the summation notation, specifically the limits of summation, which they believe should be from k=0 to 4. Additionally, there is a critique regarding the polynomial representation of the Taylor series.

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Homework Statement


Find the Taylor Polynomial of degree 3 for the function f(x) = ln3x about a = 1/3

Homework Equations


None

The Attempt at a Solution


I have found up to the fourth derivative of f(x) along with the values of the derivatives at x = 1/3.

At this point i get Σ{(-1)kk!fk(1/3)}, but am unsure of whether or not this is correct or if I am missing something. Also, not sure of what should go on top of an below the summation symbol...I think its 4 and k=0.

Thanks for your help.
 
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Nick_273 said:

Homework Statement


Find the Taylor Polynomial of degree 3 for the function f(x) = ln3x about a = 1/3


Homework Equations


None


The Attempt at a Solution


I have found up to the fourth derivative of f(x) along with the values of the derivatives at x = 1/3.

At this point i get Σ{(-1)kk!fk(1/3)}, but am unsure of whether or not this is correct or if I am missing something. Also, not sure of what should go on top of an below the summation symbol...I think its 4 and k=0.

Thanks for your help.

I think the taylor polynomial should be a polynomial. That doesn't look like a polynomial to me.
 

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