Taylor Polynomials: Why Abs(0) Doesn't Have Center at Xo=0

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ado1lz6
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Why does f(x) = abs (0) not have the first Taylor polynomial center at Xo = 0 ?
Does it have second Taylor polynomial center at Xo = 0 ?
 
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ado1lz6 said:
Why does f(x) = abs (0) not have the first Taylor polynomial center at Xo = 0 ?
Does it have second Taylor polynomial center at Xo = 0 ?

What is the derivative of |x| at x= 0?
 
That only explains that f(x) does not have second Taylor polynomial center at Xo=0. What about the first Taylor polynomial ?
Thanks a lot for reply