Tell if the impedance is complex inductive

[Cyrus]

question.

One of my HW problems asks the following after you solve it.

Tell if the impedance is complex inductive, capactive, or real resistive.

I said if my answer is of the form, R + 0j it is Real Resistive,

if it is R + N j it is complex Inductive

if it is R - Nj it is complex capacitive.

I said the minus sign on the complex makes it capactive. Is this correct?

 

[Andrew Mason]

question.

One of my HW problems asks the following after you solve it.

Tell if the impedance is complex inductive, capactive, or real resistive.

I said if my answer is of the form, R + 0j it is Real Resistive,

if it is R + N j it is complex Inductive

if it is R - Nj it is complex capacitive.

I said the minus sign on the complex makes it capactive. Is this correct?

I think it is just a convention. The convention is to express the reactance as positive if voltage leads current (inductive) and negative if voltage lags current (capacitive). So you are right.

AM

 

[kyle8921]

Yes, your explanation is correct. The minus sign in the complex impedance indicates that the impedance is capacitive. This means that the circuit has a capacitive element, which can store and release electrical energy. In contrast, a positive imaginary component would indicate an inductive element, which can store and release magnetic energy. A purely real impedance would indicate a purely resistive element, which dissipates energy. It is important to consider the complex nature of impedance in order to fully understand the behavior of a circuit.