Temperature change in a gas expansion

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yamata1
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Homework Statement
The fluid is a perfect gas. Constant pressure heating is broken down into two stages:
- an elementary transformation AB which is a heating at constant volume, during which
temperature and pressure vary by ##\delta T_V## and ##\delta P_V##.

-an elementary transformation BC which is a reversible adiabatic relaxation, during
which the temperature and the pressure vary respectively from ##\delta T_S## and ##\delta P=-\delta P_V##

1-Express ##\delta P_V ## as a function of ##\delta T_V##,T and P

2-Express ##\delta T_S## as a function of ##\delta P_V##,T , P and ##\gamma=\frac{C_p}{C_v}## then as a function of ##\delta T_V## and ##\gamma##.
Relevant Equations
##PV^{\gamma}=cst\; \; \; \; \;TV^{\gamma -1}=cst## and ##TP^{\frac{1-\gamma }{\gamma}}=cst##

PV=nRT , dU=TdS-PdV ,##\delta Q=C_V\deltaT## , ##\delta V =(\frac{\partial V}{\partial T})_P \delta T+(\frac{\partial V}{\partial P})_T \delta P##
1- ##\delta P_V =(\frac{\partial P}{\partial T} )_V \delta T_V##

2-##\delta V =(\frac{\partial V}{\partial T})_P \delta T+(\frac{\partial V}{\partial P})_T \delta P## so ##C_v \delta T=-P\delta V=-P((\frac{\partial V}{\partial T})_P \delta T+(\frac{\partial V}{\partial P})_T \delta P)## I can replace ##-P((\frac{\partial V}{\partial T})_P \delta T)=nR\delta T## since we have an ideal gas and make ##\gamma## appear that way.

Is there some other equation I am forgetting ?

Thank you
 
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Chestermiller said:
Using the ideal gas law, what is your actual answer for part 1 (not in terms of partial derivatives)?

For part 2, you don't need to use the first law if you use ##TP^{\frac{1-\gamma }{\gamma}}=cst##.
##\delta P_V =(\frac{\partial P}{\partial T} )_V \delta T_V =\frac{nR}{V}\delta T_V##.
I don't know how to use ##TP^{\frac{1-\gamma }{\gamma}}=cst## to make ##\delta T_S## a function of ##\delta P_V##,T,P and ##\gamma##.
 
yamata1 said:
##\delta P_V =(\frac{\partial P}{\partial T} )_V \delta T_V =\frac{nR}{V}\delta T_V##.
I get $$\delta T_V=\frac{\delta P}{P}T$$
I don't know how to use ##TP^{\frac{1-\gamma }{\gamma}}=cst## to make ##\delta T_S## a function of ##\delta P_V##,T,P and ##\gamma##.
I would write algebraically, $$(T+\delta T_V+\delta T_S)P^{\frac{1-\gamma }{\gamma}}=(T+\delta T_V)(P+\delta P)^{\frac{1-\gamma }{\gamma}}$$
 
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Chestermiller said:
I would write algebraically, $$(T+\delta T_V+\delta T_S)P^{\frac{1-\gamma }{\gamma}}=(T+\delta T_V)(P+\delta P)^{\frac{1-\gamma }{\gamma}}$$
Thank you but now I don't see a way to remove T and have ##\delta T_S## as a function of only ##\delta T_V## and ##\gamma ##.
 
Chestermiller said:
What does "Express δ##P_V## as a function of δ##T_V##,T and P" and "Express ##\delta T_S## as a function of ##\delta P_V##,T , P and ##\gamma##" mean to you?
Since δ##T_V## is a function of T and P there should be a way to change variables P and T in the formula for ##\delta T_S## and express it as a function of only δ##T_V## and ##\gamma##.
 
Chestermiller said:
Who says?
Question 2 :
Express ##\delta T_S## as a function of ##\delta P_V##,T , P and ##\gamma## first then as a function of ##\delta T_v## and ##\gamma##
 
Chestermiller said:
The "then" part can't be done unless T is also included. This is just an omission from the problem statement.
I guess so.Thank you for these clarifications.