Temperature change in a nail it's a tricky one.

[Dmitri10]

"Pounding an nail into wood makes the nail warmer. Consider a 5-g steel nail 6 cm long, and a hammer that exerts an average force of 600 N on it when driving the nail into a piece of wood. About how much hotter will the nail become? (The specific heat capacity of steel is 450 J/kgC.)"

Here's my work:
Given: m = 0.005 kg, d = 0.06 m, F = 600 N, c = 450 J/kgoC
Unknown: ΔT
Equation: W = Fd, Q = mcΔT
Substitution: W = 600 N * 0.06 W = 30 J
30 J = 0.005 kg * 450 J/kgoC * ΔT
Solution: ΔT = 16 oC

Is this correct?

 

[PhanthomJay]

"Pounding an nail into wood makes the nail warmer. Consider a 5-g steel nail 6 cm long, and a hammer that exerts an average force of 600 N on it when driving the nail into a piece of wood. About how much hotter will the nail become? (The specific heat capacity of steel is 450 J/kgC.)"

Here's my work:
Given: m = 0.005 kg, d = 0.06 m, F = 600 N, c = 450 J/kgoC
Unknown: ΔT
Equation: W = Fd, Q = mcΔT
Substitution: W = 600 N * 0.06 W = 30 J
30 J = 0.005 kg * 450 J/kgoC * ΔT
Solution: ΔT = 16 oC

Is this correct?

It does look correct, even with your typo of 30 J instead of 36 J, but you used 36 J anyway in your calc, looks good!

 

[Dmitri10]

Oh! Yes, 30 J was a typo; I actually used 36 J. Thank you for checking my work though!