1. The problem statement, all variables and given/known data A lightning flash releases about 1010J of electrical energy. If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37∘C, what are the final state and temperature of the water? The specific heat of water is 4180 J/kg⋅∘C, heat of vaporization at the boiling temperature for water is 2.256×106J/kg, the specific heat of steam is 1970 J/kg⋅∘C Find ΔT in ∘C 2. Relevant equations ΔU = Q - W Q = mCΔT Q = mL 3. The attempt at a solution I found Qwater = (50kg)(4180J/kg⋅∘C)(100-37) = 1.13167⋅10^7 J Qphase change to steam = (50kg)(2.256×106J/kg) = 1.128⋅10^8 J Qtotal = 1.13167⋅10^7 J + 1.128⋅10^8 J = 1.25967⋅10^8 J I'm not sure what to do with the energy from the lightning strike in order to find the total change in temperature.