Temperature required for new rms speed

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rubenhero
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Homework Statement


c) Find T, the temperature at which He gas molecules have an rms speed of v = 733 m/s.


Homework Equations


Vrms = √(3kT/m)


The Attempt at a Solution


(Vrms2m)/3k = T
(7332*.004kg)/(3*1.381e-23J/k) = T
5.187e25k = T

Any help with figuring out what I did wrong is appreciated!
 
Is not 'm' the mass of one MOELECULE of hydrogen?
 
You could use the following to solve if you are given the quantity of material (n):

P*V=n*R*T <=> T=(P*V)/(n*R)

For R is a constant: R=8.31
 
Thank you grzz and mtayab1994 for responding. It would be easier if the problem did provide n to use PV = nRT. I am confused, should I be using .008 kg for the mass because helium gas has 2 atoms?
 
rubenhero said:
Thank you grzz and mtayab1994 for responding. It would be easier if the problem did provide n to use PV = nRT. I am confused, should I be using .008 kg for the mass because helium gas has 2 atoms?

no you are fine with using .004kg
 
Last edited:
By the way you can use the following as well
Equation v_rms = sqrt(3RT / M_m), the root-mean-square speed of gas molecules in terms of gas constant R, temperature T and molar mass M_m.