Tennis Player Tosses A Tennis Ball Straight Up

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SUMMARY

A tennis player tosses a tennis ball straight up and catches it after 2.00 seconds at the same height. The acceleration of the ball during flight is consistently -9.81 m/s², due to gravity. The velocity of the ball at its maximum height is 0 m/s, as it momentarily stops before descending. The initial velocity of the ball can be calculated using the formula v = v0 + at, yielding an initial velocity of 19.62 m/s, and the maximum height reached by the ball is 19.62 meters.

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  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Familiarity with concepts of velocity and acceleration
  • Ability to solve quadratic equations
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  • Study kinematic equations for uniformly accelerated motion
  • Learn how to derive maximum height from initial velocity
  • Explore the effects of air resistance on projectile motion
  • Practice solving problems involving free fall and projectile motion
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Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for practical examples of motion under gravity.

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Homework Statement


A tennis player tosses a tennis ball straight up and then catches it after 2.00 s at the same height as the point of release. (a) what is the acceleration of the ball while it is in flight? (b) what is the velocity of the ball when it reaches its maximum height? Find (c) the initial velocity of the ball and (d) the maximum height it reaches.


Homework Equations





The Attempt at a Solution

 
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Have you tried anything thus far? What equations do you know that relate your unknown variables?
 
I honestly do not know where to start... I'm so lost in physics right now.
 
I would assume you are to neglect air resistance so a good place to start would be constant acceleration formulas.
 
a= v-v0/t ?.
 
that sounds good... you know your v after t=2...
 
Last edited:
I don't know my velocity though
 
what is your v at t=2?
 
Zero? Right because the ball is caught after 2 seconds in the same position it was thrown...
 
  • #10
Spot on! now you have only v0 and a to find, there might be some other formulas that you can compare to this one. Keep going and you'll figure it out.
 
  • #11
THANK YOU SO MUCH "Froster78" your help is greatly appreciated! :)
 
  • #12
No problem!
 

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